You are given an array prices where prices[i] is the price of a given stock on the ith day.
You want to maximize your profit by choosing a single day to buy one stock and choosing a different day in the future to sell that stock.
Return the maximum profit you can achieve from this transaction. If you cannot achieve any profit, return 0.
Example 1:
Input: prices = [7,1,5,3,6,4]
Output: 5
/**
* @param {number[]} prices
* @return {number}
*/
var maxProfit = function(prices) {
let profit = 0;
let min = prices[0];
for (let i = 1; i < prices.length; i++) {
min = Math.min(min, prices[i]);
profit = Math.max(profit, prices[i] - min);
}
return profit;
};
- 只能選一次，找出最小價＆其之後的 profit