Suppose you have n integers labeled 1 through n. A permutation of those n integers perm (1-indexed) is considered a beautiful arrangement if for every i (1 <= i <= n), either of the following is true:
perm[i]is divisible byi.iis divisible byperm[i].- Given an integer
n, return the number of the beautiful arrangements that you can construct.
Example 1:
Input: n = 2
Output: 2
Explanation:
The first beautiful arrangement is [1,2]:
- perm[1] = 1 is divisible by i = 1
- perm[2] = 2 is divisible by i = 2
The second beautiful arrangement is [2,1]:
- perm[1] = 2 is divisible by i = 1
- i = 2 is divisible by perm[2] = 1
Example 2:
Input: n = 1
Output: 1
Constraints:
1 <= n <= 15
/**
* @param {number} n
* @return {number}
*/
var countArrangement = function(n) {
if (n === 0) return 0;
let ans = 0,
map = new Map(),
usedMap = new Map();
// 整理第i位合法nums的Map
for (let i = 1; i <= n; i++) {
usedMap.set(i, false);
let temp = [];
for (let j = 1; j <= n; j++) {
if (j % i === 0 || i % j === 0) temp.push(j);
}
map.set(i, temp);
}
// n!地遍歷各組合
function backtrack(curr) {
if (curr.length === n) {
ans++;
return;
}
let need = map.get(curr.length + 1);
for (let i = 0; i < need.length; i++) {
if (usedMap.get(need[i]) === true) continue;
curr.push(need[i]);
usedMap.set(need[i], true);
backtrack(curr);
const pop = curr.pop();
usedMap.set(need[i], false);
}
}
backtrack([]);
return ans;
};